Answer
$C=120^\circ$
$b\approx1.06$
$c\approx2.69$
Work Step by Step
1. Find the third angle $C=180-40-20=120^\circ$
2. Use the Law of Sines, we have $\frac{b}{sin20^\circ}=\frac{c}{sin120^\circ}=\frac{2}{sin40^\circ}$
3. $b=\frac{2sin20^\circ}{sin40^\circ}\approx1.06$
4. $c=\frac{2sin120^\circ}{sin40^\circ}\approx2.69$
