Chapter 7 - Applications of Trigonometric Functions - Section 7.2 The Law of Sines - 7.2 Assess Your Understanding - Page 551: 23

$C=100^\circ$ $a\approx1.31$ $b\approx1.31$

1. Find the third angle $C=180-40-40=100^\circ$ 2. Use the Law of Sines, we have $\frac{a}{sin40^\circ}=\frac{b}{sin40^\circ}=\frac{2}{sin100^\circ}$ 3. $a=\frac{2sin40^\circ}{sin100^\circ}\approx1.31$ 4. $b=\frac{2sin40^\circ}{sin100^\circ}\approx1.31$