Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 7 - Applications of Trigonometric Functions - Section 7.2 The Law of Sines - 7.2 Assess Your Understanding - Page 551: 19

Answer

$A =100^\circ$ $a \approx5.24$ $c \approx0.92$

Work Step by Step

1. Find the third angle $A=180-70-10=100^\circ$ 2. Use the Law of Sines, we have $\frac{a}{sin100^\circ}=\frac{c}{sin10^\circ}=\frac{5}{sin70^\circ}$ 3. $a=\frac{5sin100^\circ}{sin70^\circ}\approx5.24$ 4. $c=\frac{5sin10^\circ}{sin70^\circ}\approx0.92$
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