Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 7 - Applications of Trigonometric Functions - Section 7.2 The Law of Sines - 7.2 Assess Your Understanding - Page 551: 13

Answer

$C =95^\circ$ $a \approx6.36$ $c \approx9.86$

Work Step by Step

1. Find the third angle $C=180-40-45=95^\circ$ 2. Use the Law of Sines, we have $\frac{a}{sin40^\circ}=\frac{c}{sin95^\circ}=\frac{7}{sin45^\circ}$ 3. $a=\frac{7sin40^\circ}{sin45^\circ}\approx6.36$ 4. $c=\frac{7sin95^\circ}{sin45^\circ}\approx9.86$
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