Chapter 7 - Applications of Trigonometric Functions - Section 7.2 The Law of Sines - 7.2 Assess Your Understanding - Page 551: 12

$A=25^\circ$ $a\approx8.45$ $c\approx16.38$

1. Find the third angle $A=180-30-125=25^\circ$ 2. Use the Law of Sines, we have $\frac{a}{sin25^\circ}=\frac{c}{sin125^\circ}=\frac{10}{sin30^\circ}$ 3. $a=\frac{10sin25^\circ}{sin30^\circ}\approx8.45$ 4. $c=\frac{10sin125^\circ}{sin30^\circ}\approx16.38$