Answer
$\sin A \cos B-\cos A \sin B$
Work Step by Step
Recall the Difference formula for the sine function is $\sin (A-B)=\sin A \cos B-\cos A \sin B$.
Thus, the missing expression in the given statement is:
$$\sin A \cos B-\cos A \sin B$$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 7 - Applications of Trigonometric Functions - Section 7.2 The Law of Sines - 7.2 Assess Your Understanding - Page 551: 1
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