Answer
The first five terms are: $c_1 =\dfrac{1}{2}
\\c_2=1
\\c_3=\dfrac{9}{8}
\\c_4=1
\\c_5=\dfrac{25}{32}$
Work Step by Step
We are given that {$c_n$} $=\dfrac{n^{2}}{2^n}$
In order to determine the first five terms, we will have to substitute $n=1,2,3,4,5$ into the given sequence {$c_n$}:
$c_1 = \dfrac{1^2}{2^1}=\dfrac{1}{2}
\\c_2= \dfrac{2^2}{2^2}=1
\\c_3= \dfrac{3^2}{2^3}=\dfrac{9}{8}
\\c_4= \dfrac{4^2}{2^4}=\dfrac{16}{16}=1
\\c_5= \dfrac{5^2}{2^5}=\dfrac{25}{32}$
