Answer
The first five terms are:
$s_1=\dfrac{3}{2} \\ s_2=\dfrac{5}{4} \\ s_3=\dfrac{7}{6} \\s_4 =\dfrac{9}{8} \\s_5 =\dfrac{11}{10}$
Work Step by Step
We are given that {$a_n$} $=\dfrac{2n+1}{2n}$
In order to determine the first five terms, we will have to substitute $n=1,2,3,4,5$ into the given sequence {$a_n$}:
$s_1=\dfrac{2(1)+1}{2(1)}=\dfrac{3}{2} \\ s_2= \dfrac{2(2)+1}{2(2)}=\dfrac{5}{4} \\ s_3=\dfrac{2(3)+1}{2(3)}=\dfrac{7}{6} \\s_4= \dfrac{2(4)+1}{2(4)}=\dfrac{9}{8} \\s_5 =\dfrac{2(5)+1}{2(5)}=\dfrac{11}{10}$
