Answer
$132$
Work Step by Step
We know that $n!=n\cdot(n-1)\cdot (n-2)...\cdot 3\cdot2\cdot 1$
Use this definition to obtain:
$$\require{cancel} \displaystyle \frac{12!}{10!} =\frac{12 \cdot 11 \cdot \cancel{10}}{\cancel{10!}}\\
=(12) (11) \\
=132$$
