Answer
$362, 880$
Work Step by Step
We know that $n!=n\cdot(n-1)\cdot (n-2)...\cdot 3\cdot2\cdot 1$ and $0 !=1$
Use this information to obtain:
$9!=9\cdot8\cdot7\cdot6\cdot5\cdot4\cdot3\cdot2\cdot1=362, 880$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 11 - Sequences; Induction; the Binomial Theorem - Section 11.1 Sequences - 11.1 Assess Your Understanding - Page 827: 10
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