## Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

$362, 880$
We know that $n!=n\cdot(n-1)\cdot (n-2)...\cdot 3\cdot2\cdot 1$ and $0 !=1$ Use this information to obtain: $9!=9\cdot8\cdot7\cdot6\cdot5\cdot4\cdot3\cdot2\cdot1=362, 880$