Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 11 - Sequences; Induction; the Binomial Theorem - Section 11.1 Sequences - 11.1 Assess Your Understanding - Page 827: 24

Answer

$a_1 =3 \\a_2= \dfrac{9}{2} \\a_3=9 \\a_4=\dfrac{81}{4} \\a_5= \dfrac{243}{5}$

Work Step by Step

We are given that {$a_n$} $= \dfrac{3^n}{n}$ In order to determine the first five terms, we will have to substitute $n=1,2,3,4,5$ into the given sequence {$a_n$}: $a_1 = \dfrac{(3)^1}{1}=\dfrac{3}{1}=3 \\a_2= \dfrac{(3)^2}{2}=\dfrac{9}{2} \\a_3= \dfrac{(3)^3}{3}=\dfrac{27}{3}=9 \\a_4= \dfrac{(3)^4}{4}=\dfrac{81}{4} \\a_5= \dfrac{(3)^5}{5}=\dfrac{243}{5}$
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