Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 11 - Sequences; Induction; the Binomial Theorem - Section 11.1 Sequences - 11.1 Assess Your Understanding - Page 827: 13

Answer

$1260$

Work Step by Step

We know that $n!=n\cdot(n-1)\cdot (n-2)\cdot 3\cdot2\cdot 1$ Use this definition to obtain: $$\require{cancel} \displaystyle \frac{3! \cdot 7!}{4!} =\frac{(3 \cdot 2 \cdot 1 ) \cdot (7 \cdot6\cdot5\cdot \cancel{4})}{\cancel{4!}}\\ =(6) (7)(6)( 5 ) \\ =1260$$
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