Answer
$x=\dfrac{1}{2}$ and $y=2$
Work Step by Step
We need to solve the given system of equations:
$2x-y=-1 ...(1)$
and $x+\dfrac{1}{2}y=\dfrac{3}{2} ...(2)$
First, we will multiply equation (2) by $2$ to get
$2x+y=3 ...(3)$
Now, add equations (1) and (3)
$2x+2x+y-y=-1+3$
$4x=2$
Next, solve for $x$:
$x=\dfrac{1}{2}$
Back substitute $x$ into Equation (1) to solve for $y$:
$y=(2) (\dfrac{1}{2})+1 \implies y=2$
