## Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

$x=-1, y =2 \text{ or } (-1, 2)$
The system of equations is given by the following two equations: \begin{cases} x+3y=5 \hspace{20pt} (1)\3mm] 2x-3y=-8 \hspace{20pt} (2) \end{cases} \text{The coefficients of y in the two equations are additive inverses.} \text{Therefore, we add the two equations to eliminate y"} \[ \begin{aligned} &x+3y=5 \\[2mm] &2x-3y=-8 \\[3mm] \hline & 3x=-3 \\[2mm] &x =-1 \end{aligned} \text{Substituting in equation (1) for } x=-1 gives:-1+3y=5\\[3mm]3y=5+1 \\[3mm] 3y=6 \\[3mm] y=2 Therefore, the solution is: $\boxed{x=-1 \hspace{20pt} y =2}$