Chapter 10 - Systems of Equations and Inequalities - Section 10.1 Systems of Linear Equations: Substitution and Elimination - 10.1 Assess Your Understanding - Page 734: 23

$(\frac{1}{3},-\frac{1}{6})$

1. Multiply 2 to the first equation to get $6x-12y=4$ 2. Multiply 3 to the second equation to get $15x+12y=3$ 3. Add up the two equations above to get $21x=7$, thus $x=\frac{1}{3}$ 4. Back substitute $x$ to the first equation to get $3(\frac{1}{3})-6y=2$, thus $y=-\frac{1}{6}$ 5. The solution pair is $(\frac{1}{3},-\frac{1}{6})$