Chapter 10 - Systems of Equations and Inequalities - Section 10.1 Systems of Linear Equations: Substitution and Elimination - 10.1 Assess Your Understanding - Page 734: 24

$(-\frac{5}{3},1)$

1. Multiply 3 to the first equation to get $6x+12y=2$ 2. Multiply -2 to the second equation to get $-6x+10y=20$ 3. Add up the two equations above to get $22y=22$, thus $y=1$ 4. Back substitute $y$ to the second equation to get $3x-5(1)=-10$, thus $x=-\frac{5}{3}$ 5. The solution pair is $(-\frac{5}{3},1)$