Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 10 - Systems of Equations and Inequalities - Section 10.1 Systems of Linear Equations: Substitution and Elimination - 10.1 Assess Your Understanding - Page 734: 37

Answer

$x=\dfrac{4}{3}$ and $ y=\dfrac{1}{5}$

Work Step by Step

We need to solve the given system of equations: $3x-5y=3 ....(1)$ $15x+5y=21 ...(2)$ First, we add the two equations (1) and (2). $3x+15x-5y+5y=3+21$ $18x=24 \\ x=\dfrac{24}{18 } \\ x=\dfrac{4}{3}$ Now, that we solved for $x$, we back substitute into Equation (1) to solve $y$: $5y=(3)( \dfrac{4}{3})-3 \\ 5y=1 \\ y=\dfrac{1}{5}$
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