Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 10 - Systems of Equations and Inequalities - Section 10.1 Systems of Linear Equations: Substitution and Elimination - 10.1 Assess Your Understanding - Page 734: 18

Answer

$x=1, y =-4 \text{ or } (1, -4)$

Work Step by Step

The system of equations is given by the following two equations: $$\begin{cases} x+2y=-7 \hspace{20pt} (1)\\[3mm] x+y=-3 \hspace{20pt} (2) \end{cases}$$ $\text{Multiplying equation (1) by -1 so that the coefficients of x}\\ \text{ in the two equations are additive inverses}$ $-x-2y = 7 \hspace{20pt} (1)$ $\text{Therefore, we add the two equations to eliminate x}$ \[ \begin{aligned} &-x-2y = 7\\[2mm] &x+y=-3 \\[3mm] \hline & -y=4 \\[2mm] &y =-4 \end{aligned} \] $\text{Substituting in equation (2) for } y=-4$ $$x-4=-3 \\[3mm]x=-3+4 \\[3mm] x=1$$ Therefore, the solution is: $\boxed{x=1 \hspace{20pt} y =-4}$
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