Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 10 - Systems of Equations and Inequalities - Section 10.1 Systems of Linear Equations: Substitution and Elimination - 10.1 Assess Your Understanding - Page 734: 45

Answer

No solutions

Work Step by Step

We need to solve the given system of equations: $x -y -z =1 ...(1) \\ 2x +3y+z =2 ...(2) \\ 3x +2y =0 ...(3) $ First, we add equations (1) and (2): $x+2x+3y-y+z-z=1+2$ $3x+2y=3$ (4) Notice that $z$ is eliminated. Now, subtract equations (3) and (4): $3x-3x+2y-2y=3-0$ $0=3$ Since $0$ never equals $3$, the system of equations is inconsistent and has no solutions.
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