Chapter 10 - Systems of Equations and Inequalities - Section 10.1 Systems of Linear Equations: Substitution and Elimination - 10.1 Assess Your Understanding - Page 734: 27

$(\frac{3}{2},3)$

1. Multiply 2 to the first equation to get $4x-2y=0$ 2. Add the above to the second equation to get $8x=12$, thus $x=\frac{3}{2}$ 3. Back substitute $x$ to the first equation to get $2(\frac{3}{2})-y=0$, thus $y=3$ 4. The solution pair is $(\frac{3}{2},3)$