Answer
$\left( 2b+c-4\right) \left( 2b+c+4\right) $
Work Step by Step
$4b^{2}+4bc+c^{2}-16=\left( 2b\right) ^{2}+2\times \left( 2b\right) \times c+c^{2}-4^{2}=\left( 2b+c\right) ^{2}-4^{2}=\left( 2b+c-4\right) \left( 2b+c+4\right) $
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter R - Review of Basic Concepts - R.4 Factoring Polynomials - R.4 Exercises - Page 44: 95
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
