Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.4 Factoring Polynomials - R.4 Exercises: 95

Answer

$\left( 2b+c-4\right) \left( 2b+c+4\right) $

Work Step by Step

$4b^{2}+4bc+c^{2}-16=\left( 2b\right) ^{2}+2\times \left( 2b\right) \times c+c^{2}-4^{2}=\left( 2b+c\right) ^{2}-4^{2}=\left( 2b+c-4\right) \left( 2b+c+4\right) $
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