Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.4 Factoring Polynomials - R.4 Exercises: 74

Answer

$\color{blue}{(3-r)(9+3r+r^2)}$

Work Step by Step

With $27=3^3$, the given polynomial is equivalent to: $=3^3-r^3$ Factor using the formula $x^3-y^3=(x-y)(x^2+xy+y^2)$ with $x=3$ and $y=r$ to obtain: $=(3-r)(3^2+3\cdot r + r^2) \\=\color{blue}{(3-r)(9+3r+r^2)}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.