Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.4 Factoring Polynomials - R.4 Exercises - Page 44: 110



Work Step by Step

100$r^2$ - 169$s^2$ = $(10r)^2$ - $(13s)^2$ Now, $a^2$ - $b^2$ = (a+b)(a-b) and a = 10r , b = 13s Which implies, = (10r+13s)(10r-13s) which is the answer
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