## Precalculus (6th Edition)

Published by Pearson

# Chapter R - Review of Basic Concepts - R.4 Factoring Polynomials - R.4 Exercises - Page 44: 101

#### Answer

$=\left( 2z+7\right) ^{2}$

#### Work Step by Step

$4z^{2}+28z+49=\left( 2z\right) ^{2}+2\times \left( 2z\right) \times 7+7^{2}=\left( 2z+7\right) ^{2}$

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