Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.4 Factoring Polynomials - R.4 Exercises: 88

Answer

$x\left( x^{2}-12x+16\right) $

Work Step by Step

$\left( x-4\right) ^{3}+64=\left( x-4\right) ^{3}+4^{3}=\left( \left( x-4\right) +4\right) \left( \left( x-4\right) ^{2}-4\times \left( x+4\right) +4^{2}\right) =x\left( x^{2}-12x+16\right) $
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