Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.4 Factoring Polynomials - R.4 Exercises - Page 44: 66



Work Step by Step

Note that $100=10^2$. Thus, the given binomial is equivalent to: $=(p-2q)^2-10^2$ Factor the binomial using the formula $a^2-b^2=(a+b)(a-b)$ where $a=p-2q$ and $y=10$ to obtain: $=[(p-2q)+10[(p-2q)-10] \\=\color{blue}{(p-2q+10)(p-2q-10))}$
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