Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.4 Factoring Polynomials - R.4 Exercises - Page 44: 107

Answer

$9(x+2)(3x^2+4)$

Work Step by Step

Use the cubic formula, we have: $64+(3x+2)^3=(3x+2)^3+4^3=(3x+2+4)[(3x+2)^2-(3x+2)(4)+16]=(3x+6)(9x^2+12)=9(x+2)(3x^2+4)$
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