Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.4 Factoring Polynomials - R.4 Exercises - Page 44: 36

Answer

$(2h+3)(4h-7)$

Work Step by Step

When factoring $ax^{2}+bx+c$, we search for factors of $ac$ whose sum is $b,$ and, if we find them, we rewrite $bx$ and proceed to factor in groups. Here, factors of $8\times(-21)=-168$ that add to $-2$ are $-14$ and $+12.$ $8h^{2}-2h-21=8h^{2}+12h-14h-21$ $=\left(8h^{2}+12h\right)+(-14h-21)$ $=4h(2h+3)-7(2h+3)$ $=(2h+3)(4h-7)$
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