## Precalculus (6th Edition)

(6p + 5q)(36$p^2$ + 25$q^2$ - 30pq)
216$p^3$ + 125$q^3$ = $(6p)^3$ + $(5q)^3$ Now, $a^3$ + $b^3$ = (a+b)($a^2$ + $b^2$ - ab) and a = 6p , b = 5q Which implies, = (6p + 5q)(36$p^2$ + 25$q^2$ - 30pq) which is the answer