Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.4 Factoring Polynomials - R.4 Exercises - Page 44: 73



Work Step by Step

With $8=2^3$, the given polynomial is equivalent to: $=2^3-a^3$ Factor using the formula $x^3-y^3=(x-y)(x^2+xy+y^2)$ with $x=2$ and $y=a$ to obtain: $=(2-a)(2^2+2\cdot a + a^2) \\=(2-a)(4+2a+a^2)$
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