Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.4 Factoring Polynomials - R.4 Exercises - Page 44: 93



Work Step by Step

Substitute $u=t^{2}.$ $12t^{4}-t^{2}-35=12u^{2}-u-35=...$ When factoring $ax^{2}+bx+c$, we search for factors of $ac=-12\cdot 35=-420$ whose sum is $b=-1,$ Here, these factors are $-21$ and $+20$ $...=12u^{2}+20u-21u-35=$ $=4u(3u+5)-7(3u+5)$ $=(3u+5)(4u-7)$ ... bring back $t$ $=(3t^{2}+5)(4t^{2}-7)$
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