Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.3 - Radicals and Rational Exponents - Exercise Set - Page 45: 8



Work Step by Step

RECALL: For non-negative real numbers a, $\sqrt{a^2}=a$. Simplify the radicand, then use the rule above: $\sqrt{169} \\=\sqrt{13^2} \\=13.$
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