Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.3 - Radicals and Rational Exponents - Exercise Set: 20

Answer

$y\sqrt{y}$

Work Step by Step

RECALL: (i) For any non-negative real numbers $a$ and $b$, $\sqrt{ab} = \sqrt{a}\cdot \sqrt{b}$ and $\sqrt{a} \cdot \sqrt{b} = \sqrt{ab}$. (ii) For any non-negative real number $a$, $\sqrt{a^2}=a$. Factor the radicand so that one of the factors is a perfect square to obtain $\\\sqrt{y^2(y)}.$ Use rule (i) above to obtain $\sqrt{y^2} \cdot \sqrt{y}.$ Use rule (ii) above to obtain $y\sqrt{y}.$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.