Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.3 - Radicals and Rational Exponents - Exercise Set - Page 45: 12

Answer

$17$

Work Step by Step

RECALL: For negative real numbers $a$, $\sqrt{a^2}=|a|$. Use the rule above, where $a=-17$ to obtain $\sqrt{(-17)^2}=|-17| = 17$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.