Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.3 - Radicals and Rational Exponents - Exercise Set: 12

Answer

$17$

Work Step by Step

RECALL: For negative real numbers $a$, $\sqrt{a^2}=|a|$. Use the rule above, where $a=-17$ to obtain $\sqrt{(-17)^2}=|-17| = 17$.
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