Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.3 - Radicals and Rational Exponents - Exercise Set - Page 45: 39



Work Step by Step

Simplify each radical to obtain $\sqrt{25(2x)} - \sqrt{4(2x)} \\=\sqrt{5^2(2x)}-\sqrt{2^2(2x)} \\=5\sqrt{2x}-2\sqrt{2x}.$ RECALL: The distributive property states that for any real numbers a, b, and c, $(ac-bc)=(a-b)c.$ Use the rule above to obtain $(5-2)\sqrt{2x} \\=3\sqrt{2x}.$
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