Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.3 - Radicals and Rational Exponents - Exercise Set - Page 45: 73



Work Step by Step

Using the properties of radicals and exponents, the given expression simplifies to $\sqrt[5]{\dfrac{64x^6}{2x}} \\=\sqrt[5]{32x^{6-1}} \\=\sqrt[5]{32x^5} \\=\sqrt[5]{2^5x^5} \\=\sqrt[5]{(2x)^5} \\=2x.$
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