Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.3 - Radicals and Rational Exponents - Exercise Set: 11

Answer

$13$

Work Step by Step

RECALL: For negative real numbers $a$, $\sqrt{a^2}=|a|$. Use the rule above, where $a=-13$ to obtain $\sqrt{(-13)^2}=|-13| = 13$.
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