Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.3 - Radicals and Rational Exponents - Exercise Set: 41

Answer

$34\sqrt{2}$

Work Step by Step

Simplify each radical to obtain $3\sqrt{9(2)} + 5\sqrt{25(2)} \\=3\sqrt{3^2(2)}+5\sqrt{5^2(2)} \\=3\cdot3\sqrt{2}+5\cdot5\sqrt{2} \\=9\sqrt{2}+25\sqrt{2}.$ RECALL: The distributive property states that for any real numbers a, b, and c, $(ac+bc)=(a+b)c.$ Use the rule above to obtain: $(9+25)\sqrt{2} \\=34\sqrt{2}.$
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