## Precalculus (6th Edition) Blitzer

$\dfrac{1}{2}$
RECALL: (i) $\sqrt[n]{a^n}=a$ when $n$ is odd. (ii) $\sqrt[n]{a^n}=|a|$ when $n$ is even. Write the radicand in exponential form (as a sixth power) to obtain $\sqrt[6]{\left(\dfrac{1}{2}\right)^6}.$ Use rule (ii) above to obtain $\sqrt[6]{\left(\dfrac{1}{2}\right)^6} = \bigg|\dfrac{1}{2}\bigg|=\dfrac{1}{2}.$