## Precalculus (6th Edition) Blitzer

Published by Pearson

# Chapter P - Section P.3 - Radicals and Rational Exponents - Exercise Set: 3

#### Answer

$-6$

#### Work Step by Step

RECALL: For non-negative real numbers $a$, $\sqrt{a^2}=a$. Write the radicand (expression inside the radical sign) as a square to obtain $-\sqrt{6^2}$. Use the rule above to obtain $-6$.

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