Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.3 - Radicals and Rational Exponents - Exercise Set - Page 45: 37



Work Step by Step

Simplify each radical to obtain $\sqrt{4(2)} + 3\sqrt{2} \\=\sqrt{2^2(2)}+3\sqrt{2} \\=2\sqrt{2}+3\sqrt{2}.$ RECALL: The distributive property states that for any real numbers a, b, and c, $(ac+bc)=(a+b)c.$ Use the rule above to obtain $(2+3)\sqrt{2} \\=5\sqrt{2}.$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.