Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.3 - Radicals and Rational Exponents - Exercise Set: 37

Answer

$5\sqrt{2}$

Work Step by Step

Simplify each radical to obtain $\sqrt{4(2)} + 3\sqrt{2} \\=\sqrt{2^2(2)}+3\sqrt{2} \\=2\sqrt{2}+3\sqrt{2}.$ RECALL: The distributive property states that for any real numbers a, b, and c, $(ac+bc)=(a+b)c.$ Use the rule above to obtain $(2+3)\sqrt{2} \\=5\sqrt{2}.$
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