## Precalculus (6th Edition) Blitzer

$-2c$
RECALL: (1) $\sin{(-t)} = -\sin{t}$ (2) $\cos{(-t)} = \cos{t}$ (3) $\tan{(-t)} = -\tan{t}$ Use the given and rule (3) above to obtain: $=-\tan{t} -\tan{t} \\=-c - c \\=-2c$