Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.2 - Trigonometric Functions: The Unit Circle - Exercise Set: 40

Answer

$\sqrt 2$

Work Step by Step

csc($\frac{\pi}{4}$ + 2$\pi$) = csc$\frac{\pi}{4}$ csc$\frac{\pi}{4}$ = $\frac{1}{sin\frac{\pi}{4}}$ csc$\frac{\pi}{4}$ = $\frac{1}{\frac{\sqrt 2}{2}}$ = $\sqrt 2$
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