Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.2 - Trigonometric Functions: The Unit Circle - Exercise Set - Page 548: 19


a.)$\frac{\sqrt 3}{2}$ b.)$\frac{\sqrt 3}{2}$

Work Step by Step

a.)cos $\frac{\pi}{6}$ corresponds to x value. cos $\frac{\pi}{6}$ = $\frac{\sqrt 3}{2}$. b.)Cosine is an even function, so cos(-t) = cos t. cos-$\frac{\pi}{6}$ = cos$\frac{\pi}{6}$ = $\frac{\sqrt 3}{2}$
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