Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.2 - Trigonometric Functions: The Unit Circle - Exercise Set - Page 548: 46

Answer

-1

Work Step by Step

tan(-t) = -tant tan(-$\frac{9\pi}{4}$) = -tan$\frac{9\pi}{4}$ -tan($\frac{\pi}{4}$ + 2$\pi$) = -tan$\frac{\pi}{4}$ -tan$\frac{\pi}{4}$ = -1
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