Answer
1
Work Step by Step
1 + $tan^{2}x$ = $sec^{2}x$ for all x
$sec^{2}x$ - $tan^{2}x$ = 1.
So for x = $\frac{\pi}{3}$,
$sec^{2}\frac{\pi}{3}$ - $tan^{2}\frac{\pi}{3}$ = 1.
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 4 - Section 4.2 - Trigonometric Functions: The Unit Circle - Exercise Set - Page 548: 37
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