Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.2 - Trigonometric Functions: The Unit Circle - Exercise Set - Page 548: 42


$\sqrt 2$

Work Step by Step

sec(-$\frac{9\pi}{4}$) = sec $\frac{9\pi}{4}$ sec($\frac{\pi}{4}$ + 2$\pi$) = sec$\frac{\pi}{4}$ sec $\frac{\pi}{4}$=$\frac{1}{cos \frac{\pi}{4}}$ sec $\frac{\pi}{4}$ =$\frac{1}{\frac{\sqrt 2}{2}}$ = $\sqrt 2$
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