Answer
a.)-$\sqrt 3$
b.)$\sqrt 3$
Work Step by Step
a.)tan$\frac{5\pi}{3}$ corresponds to $\frac{y}{x}$ value.
tan$\frac{5\pi}{3}$ = $\frac{-\frac{\sqrt 3}{2}}{\frac{1}{2}}$ = -$\sqrt 3$
b.)Tangent is an odd function, so tan(-t) = -tant.
tan-$\frac{5\pi}{3}$ = - tan$\frac{5\pi}{3}$ = $\sqrt 3$