Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.2 - Trigonometric Functions: The Unit Circle - Exercise Set: 23

Answer

a.)-$\sqrt 3$ b.)$\sqrt 3$

Work Step by Step

a.)tan$\frac{5\pi}{3}$ corresponds to $\frac{y}{x}$ value. tan$\frac{5\pi}{3}$ = $\frac{-\frac{\sqrt 3}{2}}{\frac{1}{2}}$ = -$\sqrt 3$ b.)Tangent is an odd function, so tan(-t) = -tant. tan-$\frac{5\pi}{3}$ = - tan$\frac{5\pi}{3}$ = $\sqrt 3$
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