Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.2 - Trigonometric Functions: The Unit Circle - Exercise Set - Page 548: 21

Answer

a.)$\frac{1}{2}$ b.)-$\frac{1}{2}$

Work Step by Step

a.)sin$\frac{5\pi}{6}$ corresponds to y value. sin$\frac{5\pi}{6}$ = $\frac{1}{2}$ b.)Sine is an odd function, so sin(-t) = -sin t. sin-$\frac{5\pi}{6}$ = - sin$\frac{5\pi}{6}$ = -$\frac{1}{2}$
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