Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.2 - Trigonometric Functions: The Unit Circle - Exercise Set: 22

Answer

a.) $\frac{\sqrt 3}{2}$ b.) -$\frac{\sqrt 3}{2}$

Work Step by Step

a.)sin$\frac{2\pi}{3}$ corresponds to y value. sin$\frac{2\pi}{3}$ = $\frac{\sqrt 3}{2}$ b.)Sine is an odd function, so sin(-t) = -sin t. sin-$\frac{2\pi}{3}$ = - sin$\frac{2\pi}{3}$ = -$\frac{\sqrt 3}{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.